64^2+48^2=c^2

Solution for 64^2+48^2=c^2 equation:

64^2+48^2=c^2

We move all terms to the left:

64^2+48^2-(c^2)=0

We add all the numbers together, and all the variables

-1c^2+6400=0

a = -1; b = 0; c = +6400;
Δ = b2-4ac
Δ = 02-4·(-1)·6400
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*-1}=\frac{-160}{-2}
=+80
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*-1}=\frac{160}{-2}
=-80
$